Solve 8(7)^2+5(7)+4/2(7)^2+1

$$\frac { 8 ( 7 ) ^ { 2 } + 5 ( 7 ) + 4 } { 2 ( 7 ) ^ { 2 } + 1 }$$

Evaluate

$$\frac{431}{99}\approx 4.353535354$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$\frac{8\times 49+5\times 7+4}{2\times 7^{2}+1}$$

Multiply 8 and 49 to get 392.

$$\frac{392+5\times 7+4}{2\times 7^{2}+1}$$

Multiply 5 and 7 to get 35.

$$\frac{392+35+4}{2\times 7^{2}+1}$$

Add 392 and 35 to get 427.

$$\frac{427+4}{2\times 7^{2}+1}$$

Add 427 and 4 to get 431.

$$\frac{431}{2\times 7^{2}+1}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{431}{2\times 49+1}$$

Multiply 2 and 49 to get 98.

$$\frac{431}{98+1}$$

Add 98 and 1 to get 99.

$$\frac{431}{99}$$

Factor

$$\frac{431}{3 ^ {2} \cdot 11} = 4\frac{35}{99} = 4.353535353535354$$