Solve for x
x=-\frac{8}{6-y}
y\neq 6
Solve for y
y=6+\frac{8}{x}
x\neq 0
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8+x\times 6=yx
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
8+x\times 6-yx=0
Subtract yx from both sides.
x\times 6-yx=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
\left(6-y\right)x=-8
Combine all terms containing x.
\frac{\left(6-y\right)x}{6-y}=-\frac{8}{6-y}
Divide both sides by 6-y.
x=-\frac{8}{6-y}
Dividing by 6-y undoes the multiplication by 6-y.
x=-\frac{8}{6-y}\text{, }x\neq 0
Variable x cannot be equal to 0.
8+x\times 6=yx
Multiply both sides of the equation by x.
yx=8+x\times 6
Swap sides so that all variable terms are on the left hand side.
xy=6x+8
The equation is in standard form.
\frac{xy}{x}=\frac{6x+8}{x}
Divide both sides by x.
y=\frac{6x+8}{x}
Dividing by x undoes the multiplication by x.
y=6+\frac{8}{x}
Divide 6x+8 by x.
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