Solve 8/9*(9+3/4)-1/3

$$\frac { 8 } { 9 } \times ( 9 + \frac { 3 } { 4 } ) - \frac { 1 } { 3 }$$

Evaluate

$$\frac{25}{3}\approx 8.333333333$$

Solution Steps

Convert 9 to fraction \frac{36}{4}.

$$\frac{8}{9}\left(\frac{36}{4}+\frac{3}{4}\right)-\frac{1}{3}$$

Since \frac{36}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{8}{9}\times \frac{36+3}{4}-\frac{1}{3}$$

Add 36 and 3 to get 39.

$$\frac{8}{9}\times \frac{39}{4}-\frac{1}{3}$$

Multiply \frac{8}{9} times \frac{39}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 39}{9\times 4}-\frac{1}{3}$$

Do the multiplications in the fraction \frac{8\times 39}{9\times 4}.

$$\frac{312}{36}-\frac{1}{3}$$

Reduce the fraction \frac{312}{36} to lowest terms by extracting and canceling out 12.

$$\frac{26}{3}-\frac{1}{3}$$

Since \frac{26}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{26-1}{3}$$

Subtract 1 from 26 to get 25.

$$\frac{25}{3}$$

Factor

$$\frac{5 ^ {2}}{3} = 8\frac{1}{3} = 8.333333333333334$$