\frac { 8 } { 9 } \cdot ( \frac { 15 } { 26 } : \frac { 20 } { 30 } ) = ( So
Solve for S
S=\frac{10}{13o}
o\neq 0
Solve for o
o=\frac{10}{13S}
S\neq 0
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\frac{8}{9}\times \frac{15\times 30}{26\times 20}=So
Divide \frac{15}{26} by \frac{20}{30} by multiplying \frac{15}{26} by the reciprocal of \frac{20}{30}.
\frac{8}{9}\times \frac{3\times 15}{4\times 13}=So
Cancel out 2\times 5 in both numerator and denominator.
\frac{8}{9}\times \frac{45}{4\times 13}=So
Multiply 3 and 15 to get 45.
\frac{8}{9}\times \frac{45}{52}=So
Multiply 4 and 13 to get 52.
\frac{10}{13}=So
Multiply \frac{8}{9} and \frac{45}{52} to get \frac{10}{13}.
So=\frac{10}{13}
Swap sides so that all variable terms are on the left hand side.
oS=\frac{10}{13}
The equation is in standard form.
\frac{oS}{o}=\frac{\frac{10}{13}}{o}
Divide both sides by o.
S=\frac{\frac{10}{13}}{o}
Dividing by o undoes the multiplication by o.
S=\frac{10}{13o}
Divide \frac{10}{13} by o.
\frac{8}{9}\times \frac{15\times 30}{26\times 20}=So
Divide \frac{15}{26} by \frac{20}{30} by multiplying \frac{15}{26} by the reciprocal of \frac{20}{30}.
\frac{8}{9}\times \frac{3\times 15}{4\times 13}=So
Cancel out 2\times 5 in both numerator and denominator.
\frac{8}{9}\times \frac{45}{4\times 13}=So
Multiply 3 and 15 to get 45.
\frac{8}{9}\times \frac{45}{52}=So
Multiply 4 and 13 to get 52.
\frac{10}{13}=So
Multiply \frac{8}{9} and \frac{45}{52} to get \frac{10}{13}.
So=\frac{10}{13}
Swap sides so that all variable terms are on the left hand side.
\frac{So}{S}=\frac{\frac{10}{13}}{S}
Divide both sides by S.
o=\frac{\frac{10}{13}}{S}
Dividing by S undoes the multiplication by S.
o=\frac{10}{13S}
Divide \frac{10}{13} by S.
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