Solve 8/6-c=16/6+c

$$\frac { 8 } { 6 - c } = \frac { 16 } { 6 + c }$$

Solve for c

$$c=2$$

Steps for Solving Linear Equation

Variable c cannot be equal to any of the values -6,6 since division by zero is not defined. Multiply both sides of the equation by \left(c-6\right)\left(c+6\right), the least common multiple of 6-c,6+c.

$$-\left(6+c\right)\times 8=\left(c-6\right)\times 16$$

To find the opposite of 6+c, find the opposite of each term.

$$\left(-6-c\right)\times 8=\left(c-6\right)\times 16$$

Use the distributive property to multiply -6-c by 8.

$$-48-8c=\left(c-6\right)\times 16$$

Use the distributive property to multiply c-6 by 16.

$$-48-8c=16c-96$$

Subtract 16c from both sides.

$$-48-8c-16c=-96$$

Combine -8c and -16c to get -24c.

$$-48-24c=-96$$

Add 48 to both sides.

$$-24c=-96+48$$

Add -96 and 48 to get -48.

$$-24c=-48$$

Divide both sides by -24.

$$c=\frac{-48}{-24}$$

Divide -48 by -24 to get 2.

$$c=2$$