Solve for x
x=28
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\left(3x+1\right)\times 8=\left(5x-4\right)\times 5
Variable x cannot be equal to any of the values -\frac{1}{3},\frac{4}{5} since division by zero is not defined. Multiply both sides of the equation by \left(5x-4\right)\left(3x+1\right), the least common multiple of 5x-4,3x+1.
24x+8=\left(5x-4\right)\times 5
Use the distributive property to multiply 3x+1 by 8.
24x+8=25x-20
Use the distributive property to multiply 5x-4 by 5.
24x+8-25x=-20
Subtract 25x from both sides.
-x+8=-20
Combine 24x and -25x to get -x.
-x=-20-8
Subtract 8 from both sides.
-x=-28
Subtract 8 from -20 to get -28.
x=28
Multiply both sides by -1.
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