Solve 8/3-2{6-frac{8/a}}

$$\frac { 8 } { 3 - \frac { 2 } { 6 - \frac { 8 } { a } } }$$

Evaluate

$$\frac{2\left(3a-4\right)}{2a-3}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 6 times \frac{a}{a}.

$$\frac{8}{3-\frac{2}{\frac{6a}{a}-\frac{8}{a}}}$$

Since \frac{6a}{a} and \frac{8}{a} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8}{3-\frac{2}{\frac{6a-8}{a}}}$$

Divide 2 by \frac{6a-8}{a} by multiplying 2 by the reciprocal of \frac{6a-8}{a}.

$$\frac{8}{3-\frac{2a}{6a-8}}$$

Factor the expressions that are not already factored in \frac{2a}{6a-8}.

$$\frac{8}{3-\frac{2a}{2\left(3a-4\right)}}$$

Cancel out 2 in both numerator and denominator.

$$\frac{8}{3-\frac{a}{3a-4}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{3a-4}{3a-4}.

$$\frac{8}{\frac{3\left(3a-4\right)}{3a-4}-\frac{a}{3a-4}}$$

Since \frac{3\left(3a-4\right)}{3a-4} and \frac{a}{3a-4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8}{\frac{3\left(3a-4\right)-a}{3a-4}}$$

Do the multiplications in 3\left(3a-4\right)-a.

$$\frac{8}{\frac{9a-12-a}{3a-4}}$$

Combine like terms in 9a-12-a.

$$\frac{8}{\frac{8a-12}{3a-4}}$$

Divide 8 by \frac{8a-12}{3a-4} by multiplying 8 by the reciprocal of \frac{8a-12}{3a-4}.

$$\frac{8\left(3a-4\right)}{8a-12}$$

Factor the expressions that are not already factored.

$$\frac{8\left(3a-4\right)}{4\left(2a-3\right)}$$

Cancel out 4 in both numerator and denominator.

$$\frac{2\left(3a-4\right)}{2a-3}$$

Expand the expression.

$$\frac{6a-8}{2a-3}$$

Differentiate w.r.t. a

$$-\frac{2}{\left(2a-3\right)^{2}}$$

Steps Using Derivative Rule for Quotient

To add or subtract expressions, expand them to make their denominators the same. Multiply 6 times \frac{a}{a}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{3-\frac{2}{\frac{6a}{a}-\frac{8}{a}}})$$

Since \frac{6a}{a} and \frac{8}{a} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{3-\frac{2}{\frac{6a-8}{a}}})$$

Divide 2 by \frac{6a-8}{a} by multiplying 2 by the reciprocal of \frac{6a-8}{a}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{3-\frac{2a}{6a-8}})$$

Factor the expressions that are not already factored in \frac{2a}{6a-8}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{3-\frac{2a}{2\left(3a-4\right)}})$$

Cancel out 2 in both numerator and denominator.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{3-\frac{a}{3a-4}})$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{3a-4}{3a-4}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{\frac{3\left(3a-4\right)}{3a-4}-\frac{a}{3a-4}})$$

Since \frac{3\left(3a-4\right)}{3a-4} and \frac{a}{3a-4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{\frac{3\left(3a-4\right)-a}{3a-4}})$$

Do the multiplications in 3\left(3a-4\right)-a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{\frac{9a-12-a}{3a-4}})$$

Combine like terms in 9a-12-a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8}{\frac{8a-12}{3a-4}})$$

Divide 8 by \frac{8a-12}{3a-4} by multiplying 8 by the reciprocal of \frac{8a-12}{3a-4}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8\left(3a-4\right)}{8a-12})$$

Factor the expressions that are not already factored in \frac{8\left(3a-4\right)}{8a-12}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{8\left(3a-4\right)}{4\left(2a-3\right)})$$

Cancel out 4 in both numerator and denominator.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{2\left(3a-4\right)}{2a-3})$$

Use the distributive property to multiply 2 by 3a-4.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{6a-8}{2a-3})$$

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(2a^{1}-3\right)\frac{\mathrm{d}}{\mathrm{d}a}(6a^{1}-8)-\left(6a^{1}-8\right)\frac{\mathrm{d}}{\mathrm{d}a}(2a^{1}-3)}{\left(2a^{1}-3\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(2a^{1}-3\right)\times 6a^{1-1}-\left(6a^{1}-8\right)\times 2a^{1-1}}{\left(2a^{1}-3\right)^{2}}$$

Do the arithmetic.

$$\frac{\left(2a^{1}-3\right)\times 6a^{0}-\left(6a^{1}-8\right)\times 2a^{0}}{\left(2a^{1}-3\right)^{2}}$$

Expand using distributive property.

$$\frac{2a^{1}\times 6a^{0}-3\times 6a^{0}-\left(6a^{1}\times 2a^{0}-8\times 2a^{0}\right)}{\left(2a^{1}-3\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{2\times 6a^{1}-3\times 6a^{0}-\left(6\times 2a^{1}-8\times 2a^{0}\right)}{\left(2a^{1}-3\right)^{2}}$$

Do the arithmetic.

$$\frac{12a^{1}-18a^{0}-\left(12a^{1}-16a^{0}\right)}{\left(2a^{1}-3\right)^{2}}$$

Remove unnecessary parentheses.

$$\frac{12a^{1}-18a^{0}-12a^{1}-\left(-16a^{0}\right)}{\left(2a^{1}-3\right)^{2}}$$

Combine like terms.

$$\frac{\left(12-12\right)a^{1}+\left(-18-\left(-16\right)\right)a^{0}}{\left(2a^{1}-3\right)^{2}}$$

Subtract 12 from 12 and -16 from -18.

$$\frac{-2a^{0}}{\left(2a^{1}-3\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{-2a^{0}}{\left(2a-3\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{-2}{\left(2a-3\right)^{2}}$$