Solve 8/3-(2/7*3/6)+1/6

$$\frac { 8 } { 3 } - ( \frac { 2 } { 7 } \cdot \frac { 3 } { 6 } ) + \frac { 1 } { 6 }$$

Evaluate

$$\frac{113}{42}\approx 2.69047619$$

Solution Steps

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{8}{3}-\frac{2}{7}\times \frac{1}{2}+\frac{1}{6}$$

Multiply \frac{2}{7} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8}{3}-\frac{2\times 1}{7\times 2}+\frac{1}{6}$$

Cancel out 2 in both numerator and denominator.

$$\frac{8}{3}-\frac{1}{7}+\frac{1}{6}$$

Least common multiple of 3 and 7 is 21. Convert \frac{8}{3} and \frac{1}{7} to fractions with denominator 21.

$$\frac{56}{21}-\frac{3}{21}+\frac{1}{6}$$

Since \frac{56}{21} and \frac{3}{21} have the same denominator, subtract them by subtracting their numerators.

$$\frac{56-3}{21}+\frac{1}{6}$$

Subtract 3 from 56 to get 53.

$$\frac{53}{21}+\frac{1}{6}$$

Least common multiple of 21 and 6 is 42. Convert \frac{53}{21} and \frac{1}{6} to fractions with denominator 42.

$$\frac{106}{42}+\frac{7}{42}$$

Since \frac{106}{42} and \frac{7}{42} have the same denominator, add them by adding their numerators.

$$\frac{106+7}{42}$$

Add 106 and 7 to get 113.

$$\frac{113}{42}$$

Factor

$$\frac{113}{2 \cdot 3 \cdot 7} = 2\frac{29}{42} = 2.6904761904761907$$