Solve 8/1.6=4+4+[-3)/ED

$$\frac { 8 } { 1.6 } = \frac { 4 + 4 + [ - 3 ) } { E D }$$

Solve for D

$$D=\frac{1}{E}$$

$$E\neq 0$$

Steps for Solving Linear Equation

Variable D cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by DE.

$$DE\times \frac{8}{1.6}=4+4-3$$

Expand \frac{8}{1.6} by multiplying both numerator and the denominator by 10.

$$DE\times \frac{80}{16}=4+4-3$$

Divide 80 by 16 to get 5.

$$DE\times 5=4+4-3$$

Add 4 and 4 to get 8.

$$DE\times 5=8-3$$

Subtract 3 from 8 to get 5.

$$DE\times 5=5$$

The equation is in standard form.

$$5ED=5$$

Divide both sides by 5E.

$$\frac{5ED}{5E}=\frac{5}{5E}$$

Dividing by 5E undoes the multiplication by 5E.

$$D=\frac{5}{5E}$$

Divide 5 by 5E.

$$D=\frac{1}{E}$$

Variable D cannot be equal to 0.

$$D=\frac{1}{E}\text{, }D\neq 0$$

Solve for E

$$E=\frac{1}{D}$$

$$D\neq 0$$

Steps for Solving Linear Equation

Variable E cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by DE.

$$DE\times \frac{8}{1.6}=4+4-3$$

Expand \frac{8}{1.6} by multiplying both numerator and the denominator by 10.

$$DE\times \frac{80}{16}=4+4-3$$

Divide 80 by 16 to get 5.

$$DE\times 5=4+4-3$$

Add 4 and 4 to get 8.

$$DE\times 5=8-3$$

Subtract 3 from 8 to get 5.

$$DE\times 5=5$$

The equation is in standard form.

$$5DE=5$$

Divide both sides by 5D.

$$\frac{5DE}{5D}=\frac{5}{5D}$$

Dividing by 5D undoes the multiplication by 5D.

$$E=\frac{5}{5D}$$

Divide 5 by 5D.

$$E=\frac{1}{D}$$

Variable E cannot be equal to 0.

$$E=\frac{1}{D}\text{, }E\neq 0$$