Solve 8/1-11/5-23/10-11/2

$$\frac { 8 } { 1 } - 1 \frac { 1 } { 5 } - 2 \frac { 3 } { 10 } - 1 \frac { 1 } { 2 }$$

Evaluate

$$3$$

Solution Steps

Anything divided by one gives itself.

$$8-\frac{1\times 5+1}{5}-\frac{2\times 10+3}{10}-\frac{1\times 2+1}{2}$$

Multiply 1 and 5 to get 5.

$$8-\frac{5+1}{5}-\frac{2\times 10+3}{10}-\frac{1\times 2+1}{2}$$

Add 5 and 1 to get 6.

$$8-\frac{6}{5}-\frac{2\times 10+3}{10}-\frac{1\times 2+1}{2}$$

Convert 8 to fraction \frac{40}{5}.

$$\frac{40}{5}-\frac{6}{5}-\frac{2\times 10+3}{10}-\frac{1\times 2+1}{2}$$

Since \frac{40}{5} and \frac{6}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{40-6}{5}-\frac{2\times 10+3}{10}-\frac{1\times 2+1}{2}$$

Subtract 6 from 40 to get 34.

$$\frac{34}{5}-\frac{2\times 10+3}{10}-\frac{1\times 2+1}{2}$$

Multiply 2 and 10 to get 20.

$$\frac{34}{5}-\frac{20+3}{10}-\frac{1\times 2+1}{2}$$

Add 20 and 3 to get 23.

$$\frac{34}{5}-\frac{23}{10}-\frac{1\times 2+1}{2}$$

Least common multiple of 5 and 10 is 10. Convert \frac{34}{5} and \frac{23}{10} to fractions with denominator 10.

$$\frac{68}{10}-\frac{23}{10}-\frac{1\times 2+1}{2}$$

Since \frac{68}{10} and \frac{23}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{68-23}{10}-\frac{1\times 2+1}{2}$$

Subtract 23 from 68 to get 45.

$$\frac{45}{10}-\frac{1\times 2+1}{2}$$

Reduce the fraction \frac{45}{10} to lowest terms by extracting and canceling out 5.

$$\frac{9}{2}-\frac{1\times 2+1}{2}$$

Multiply 1 and 2 to get 2.

$$\frac{9}{2}-\frac{2+1}{2}$$

Add 2 and 1 to get 3.

$$\frac{9}{2}-\frac{3}{2}$$

Since \frac{9}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-3}{2}$$

Subtract 3 from 9 to get 6.

$$\frac{6}{2}$$

Divide 6 by 2 to get 3.

$$3$$

Factor

$$3$$