Solve 81/2+27/8/8*2=

$$\frac { 8 \frac { 1 } { 2 } + 2 \frac { 7 } { 8 } } { 8 \cdot 2 } =$$

Evaluate

$$\frac{91}{128}=0.7109375$$

Solution Steps

Multiply 8 and 2 to get 16.

$$\frac{\frac{16+1}{2}+\frac{2\times 8+7}{8}}{8\times 2}$$

Add 16 and 1 to get 17.

$$\frac{\frac{17}{2}+\frac{2\times 8+7}{8}}{8\times 2}$$

Multiply 2 and 8 to get 16.

$$\frac{\frac{17}{2}+\frac{16+7}{8}}{8\times 2}$$

Add 16 and 7 to get 23.

$$\frac{\frac{17}{2}+\frac{23}{8}}{8\times 2}$$

Least common multiple of 2 and 8 is 8. Convert \frac{17}{2} and \frac{23}{8} to fractions with denominator 8.

$$\frac{\frac{68}{8}+\frac{23}{8}}{8\times 2}$$

Since \frac{68}{8} and \frac{23}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{68+23}{8}}{8\times 2}$$

Add 68 and 23 to get 91.

$$\frac{\frac{91}{8}}{8\times 2}$$

Multiply 8 and 2 to get 16.

$$\frac{\frac{91}{8}}{16}$$

Express \frac{\frac{91}{8}}{16} as a single fraction.

$$\frac{91}{8\times 16}$$

Multiply 8 and 16 to get 128.

$$\frac{91}{128}$$

Factor

$$\frac{7 \cdot 13}{2 ^ {7}} = 0.7109375$$