Solve 8^2/9-45/6

$$\frac { 8 ^ { 2 } } { 9 } - 4 \frac { 5 } { 6 }$$

Evaluate

$$\frac{41}{18}\approx 2.277777778$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$\frac{64}{9}-\frac{4\times 6+5}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{64}{9}-\frac{24+5}{6}$$

Add 24 and 5 to get 29.

$$\frac{64}{9}-\frac{29}{6}$$

Least common multiple of 9 and 6 is 18. Convert \frac{64}{9} and \frac{29}{6} to fractions with denominator 18.

$$\frac{128}{18}-\frac{87}{18}$$

Since \frac{128}{18} and \frac{87}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{128-87}{18}$$

Subtract 87 from 128 to get 41.

$$\frac{41}{18}$$

Factor

$$\frac{41}{2 \cdot 3 ^ {2}} = 2\frac{5}{18} = 2.2777777777777777$$