Solve 8!+7!/3!*6!-(2*2+3)!

$$\frac { 8 ! + 7 ! } { 3 ! \times 6 ! - ( 2 \times 2 + 3 ) ! }$$

Evaluate

$$-63$$

Solution Steps

The factorial of 8 is 40320.

$$\frac{40320+7!}{3!\times 6!-\left(2\times 2+3\right)!}$$

The factorial of 7 is 5040.

$$\frac{40320+5040}{3!\times 6!-\left(2\times 2+3\right)!}$$

Add 40320 and 5040 to get 45360.

$$\frac{45360}{3!\times 6!-\left(2\times 2+3\right)!}$$

The factorial of 3 is 6.

$$\frac{45360}{6\times 6!-\left(2\times 2+3\right)!}$$

The factorial of 6 is 720.

$$\frac{45360}{6\times 720-\left(2\times 2+3\right)!}$$

Multiply 6 and 720 to get 4320.

$$\frac{45360}{4320-\left(2\times 2+3\right)!}$$

Multiply 2 and 2 to get 4.

$$\frac{45360}{4320-\left(4+3\right)!}$$

Add 4 and 3 to get 7.

$$\frac{45360}{4320-7!}$$

The factorial of 7 is 5040.

$$\frac{45360}{4320-5040}$$

Subtract 5040 from 4320 to get -720.

$$\frac{45360}{-720}$$

Divide 45360 by -720 to get -63.

$$-63$$

Factor

$$-63$$