Solve 72/19div2/5=12*5/15*2=60/30

$$\frac { 72 } { 19 } \div \frac { 2 } { 5 } = \frac { 12 \times 5 } { 15 \times 2 } = \frac { 60 } { 30 }$$

Verify

Solution Steps

Divide \frac{72}{19} by \frac{2}{5} by multiplying \frac{72}{19} by the reciprocal of \frac{2}{5}.

$$\frac{72}{19}\times \frac{5}{2}=\frac{12\times 5}{15\times 2}\text{ and }\frac{12\times 5}{15\times 2}=\frac{60}{30}$$

Multiply \frac{72}{19} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{72\times 5}{19\times 2}=\frac{12\times 5}{15\times 2}\text{ and }\frac{12\times 5}{15\times 2}=\frac{60}{30}$$

Do the multiplications in the fraction \frac{72\times 5}{19\times 2}.

$$\frac{360}{38}=\frac{12\times 5}{15\times 2}\text{ and }\frac{12\times 5}{15\times 2}=\frac{60}{30}$$

Reduce the fraction \frac{360}{38} to lowest terms by extracting and canceling out 2.

$$\frac{180}{19}=\frac{12\times 5}{15\times 2}\text{ and }\frac{12\times 5}{15\times 2}=\frac{60}{30}$$

Cancel out 2\times 3\times 5 in both numerator and denominator.

$$\frac{180}{19}=2\text{ and }\frac{12\times 5}{15\times 2}=\frac{60}{30}$$

Convert 2 to fraction \frac{38}{19}.

$$\frac{180}{19}=\frac{38}{19}\text{ and }\frac{12\times 5}{15\times 2}=\frac{60}{30}$$

Compare \frac{180}{19} and \frac{38}{19}.

$$\text{false}\text{ and }\frac{12\times 5}{15\times 2}=\frac{60}{30}$$

Cancel out 2\times 3\times 5 in both numerator and denominator.

$$\text{false}\text{ and }2=\frac{60}{30}$$

Divide 60 by 30 to get 2.

$$\text{false}\text{ and }2=2$$

Compare 2 and 2.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$