Solve 71^2+49^3/120+7149

$$\frac { 71 ^ { 2 } + 49 ^ { 3 } } { 120 } + 7149$$

Evaluate

$$\frac{98057}{12}\approx 8171.416666667$$

Solution Steps

Calculate 71 to the power of 2 and get 5041.

$$\frac{5041+49^{3}}{120}+7149$$

Calculate 49 to the power of 3 and get 117649.

$$\frac{5041+117649}{120}+7149$$

Add 5041 and 117649 to get 122690.

$$\frac{122690}{120}+7149$$

Reduce the fraction \frac{122690}{120} to lowest terms by extracting and canceling out 10.

$$\frac{12269}{12}+7149$$

Convert 7149 to fraction \frac{85788}{12}.

$$\frac{12269}{12}+\frac{85788}{12}$$

Since \frac{12269}{12} and \frac{85788}{12} have the same denominator, add them by adding their numerators.

$$\frac{12269+85788}{12}$$

Add 12269 and 85788 to get 98057.

$$\frac{98057}{12}$$

Factor

$$\frac{98057}{2 ^ {2} \cdot 3} = 8171\frac{5}{12} = 8171.416666666667$$