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\frac{7x-2-\left(3x-3\right)}{4x+1}
Since \frac{7x-2}{4x+1} and \frac{3x-3}{4x+1} have the same denominator, subtract them by subtracting their numerators.
\frac{7x-2-3x+3}{4x+1}
Do the multiplications in 7x-2-\left(3x-3\right).
\frac{4x+1}{4x+1}
Combine like terms in 7x-2-3x+3.
1
Cancel out 4x+1 in both numerator and denominator.
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