Solve 7a^12/36b^9*48b^3/64a^3=?

$$\frac { 7 a ^ { 12 } } { 36 b ^ { 9 } } \times \frac { 48 b ^ { 3 } } { 64 a ^ { 3 } } = ?$$

Evaluate

$$\frac{7a^{9}}{48b^{6}}$$

Solution Steps

Cancel out 16 in both numerator and denominator.

$$\frac{7a^{12}}{36b^{9}}\times \frac{3b^{3}}{4a^{3}}$$

Multiply \frac{7a^{12}}{36b^{9}} times \frac{3b^{3}}{4a^{3}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7a^{12}\times 3b^{3}}{36b^{9}\times 4a^{3}}$$

Cancel out 3a^{3}b^{3} in both numerator and denominator.

$$\frac{7a^{9}}{4\times 12b^{6}}$$

Multiply 4 and 12 to get 48.

$$\frac{7a^{9}}{48b^{6}}$$

Differentiate w.r.t. a

$$\frac{21a^{8}}{16b^{6}}$$