Solve 7/d^29-9d/9

$$\frac { 7 } { d ^ { 2 } 9 } - \frac { 9 d } { 9 }$$

Evaluate

$$-d+\frac{7}{9d^{2}}$$

Short Solution Steps

Cancel out 9 and 9.

$$\frac{7}{d^{2}\times 9}-d$$

To add or subtract expressions, expand them to make their denominators the same. Multiply d times \frac{d^{2}\times 9}{d^{2}\times 9}.

$$\frac{7}{d^{2}\times 9}-\frac{dd^{2}\times 9}{d^{2}\times 9}$$

Since \frac{7}{d^{2}\times 9} and \frac{dd^{2}\times 9}{d^{2}\times 9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-dd^{2}\times 9}{d^{2}\times 9}$$

Do the multiplications in 7-dd^{2}\times 9.

$$\frac{7-9d^{3}}{d^{2}\times 9}$$

Factor

$$\frac{7-9d^{3}}{9d^{2}}$$