Solve 7/9uy^3-2/3u^2y

$$\frac { 7 } { 9 u y ^ { 3 } } - \frac { 2 } { 3 u ^ { 2 } y }$$

Evaluate

$$-\frac{2}{3yu^{2}}+\frac{7}{9uy^{3}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 9uy^{3} and 3u^{2}y is 9u^{2}y^{3}. Multiply \frac{7}{9uy^{3}} times \frac{u}{u}. Multiply \frac{2}{3u^{2}y} times \frac{3y^{2}}{3y^{2}}.

$$\frac{7u}{9u^{2}y^{3}}-\frac{2\times 3y^{2}}{9u^{2}y^{3}}$$

Since \frac{7u}{9u^{2}y^{3}} and \frac{2\times 3y^{2}}{9u^{2}y^{3}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7u-2\times 3y^{2}}{9u^{2}y^{3}}$$

Do the multiplications in 7u-2\times 3y^{2}.

$$\frac{7u-6y^{2}}{9u^{2}y^{3}}$$

Factor

$$\frac{7u-6y^{2}}{9u^{2}y^{3}}$$