Solve 7/9*1/25+10/25*4/9

$$\frac { 7 } { 9 } \times \frac { 1 } { 25 } + \frac { 10 } { 25 } \times \frac { 4 } { 9 }$$

Evaluate

$$\frac{47}{225}\approx 0.208888889$$

Solution Steps

Multiply \frac{7}{9} times \frac{1}{25} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 1}{9\times 25}+\frac{10}{25}\times \frac{4}{9}$$

Do the multiplications in the fraction \frac{7\times 1}{9\times 25}.

$$\frac{7}{225}+\frac{10}{25}\times \frac{4}{9}$$

Reduce the fraction \frac{10}{25} to lowest terms by extracting and canceling out 5.

$$\frac{7}{225}+\frac{2}{5}\times \frac{4}{9}$$

Multiply \frac{2}{5} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{225}+\frac{2\times 4}{5\times 9}$$

Do the multiplications in the fraction \frac{2\times 4}{5\times 9}.

$$\frac{7}{225}+\frac{8}{45}$$

Least common multiple of 225 and 45 is 225. Convert \frac{7}{225} and \frac{8}{45} to fractions with denominator 225.

$$\frac{7}{225}+\frac{40}{225}$$

Since \frac{7}{225} and \frac{40}{225} have the same denominator, add them by adding their numerators.

$$\frac{7+40}{225}$$

Add 7 and 40 to get 47.

$$\frac{47}{225}$$

Factor

$$\frac{47}{3 ^ {2} \cdot 5 ^ {2}} = 0.2088888888888889$$