Solve 7/9+5/6*1/3

$$\frac { 7 } { 9 } + \frac { 5 } { 6 } \cdot \frac { 1 } { 3 }$$

Evaluate

$$\frac{19}{18}\approx 1.055555556$$

Solution Steps

Multiply \frac{5}{6} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{9}+\frac{5\times 1}{6\times 3}$$

Do the multiplications in the fraction \frac{5\times 1}{6\times 3}.

$$\frac{7}{9}+\frac{5}{18}$$

Least common multiple of 9 and 18 is 18. Convert \frac{7}{9} and \frac{5}{18} to fractions with denominator 18.

$$\frac{14}{18}+\frac{5}{18}$$

Since \frac{14}{18} and \frac{5}{18} have the same denominator, add them by adding their numerators.

$$\frac{14+5}{18}$$

Add 14 and 5 to get 19.

$$\frac{19}{18}$$

Factor

$$\frac{19}{2 \cdot 3 ^ {2}} = 1\frac{1}{18} = 1.0555555555555556$$