Solve 7/9+4/7(2/3)^2

$$\frac { 7 } { 9 } + \frac { 4 } { 7 } ( \frac { 2 } { 3 } ) ^ { 2 }$$

Evaluate

$$\frac{65}{63}\approx 1.031746032$$

Solution Steps

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{7}{9}+\frac{4}{7}\times \frac{4}{9}$$

Multiply \frac{4}{7} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{9}+\frac{4\times 4}{7\times 9}$$

Do the multiplications in the fraction \frac{4\times 4}{7\times 9}.

$$\frac{7}{9}+\frac{16}{63}$$

Least common multiple of 9 and 63 is 63. Convert \frac{7}{9} and \frac{16}{63} to fractions with denominator 63.

$$\frac{49}{63}+\frac{16}{63}$$

Since \frac{49}{63} and \frac{16}{63} have the same denominator, add them by adding their numerators.

$$\frac{49+16}{63}$$

Add 49 and 16 to get 65.

$$\frac{65}{63}$$

Factor

$$\frac{5 \cdot 13}{3 ^ {2} \cdot 7} = 1\frac{2}{63} = 1.0317460317460319$$