Solve 7/9+1/6div3/7

$$\frac { 7 } { 9 } + \frac { 1 } { 6 } \div \frac { 3 } { 7 }$$

Evaluate

$$\frac{7}{6}\approx 1.166666667$$

Solution Steps

Divide \frac{1}{6} by \frac{3}{7} by multiplying \frac{1}{6} by the reciprocal of \frac{3}{7}.

$$\frac{7}{9}+\frac{1}{6}\times \frac{7}{3}$$

Multiply \frac{1}{6} times \frac{7}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{9}+\frac{1\times 7}{6\times 3}$$

Do the multiplications in the fraction \frac{1\times 7}{6\times 3}.

$$\frac{7}{9}+\frac{7}{18}$$

Least common multiple of 9 and 18 is 18. Convert \frac{7}{9} and \frac{7}{18} to fractions with denominator 18.

$$\frac{14}{18}+\frac{7}{18}$$

Since \frac{14}{18} and \frac{7}{18} have the same denominator, add them by adding their numerators.

$$\frac{14+7}{18}$$

Add 14 and 7 to get 21.

$$\frac{21}{18}$$

Reduce the fraction \frac{21}{18} to lowest terms by extracting and canceling out 3.

$$\frac{7}{6}$$

Factor

$$\frac{7}{2 \cdot 3} = 1\frac{1}{6} = 1.1666666666666667$$