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\frac{7}{8}x\times 8x-3=y\times 8x
Multiply both sides of the equation by 8x, the least common multiple of 8,8x.
7xx-3=y\times 8x
Multiply \frac{7}{8} and 8 to get 7.
7x^{2}-3=y\times 8x
Multiply x and x to get x^{2}.
y\times 8x=7x^{2}-3
Swap sides so that all variable terms are on the left hand side.
8xy=7x^{2}-3
The equation is in standard form.
\frac{8xy}{8x}=\frac{7x^{2}-3}{8x}
Divide both sides by 8x.
y=\frac{7x^{2}-3}{8x}
Dividing by 8x undoes the multiplication by 8x.
y=\frac{7x}{8}-\frac{3}{8x}
Divide 7x^{2}-3 by 8x.