Solve 7/8x-3/8x=y

$$\frac { 7 } { 8 } x - \frac { 3 } { 8 x } = y$$

Solve for y

$$y=\frac{7x}{8}-\frac{3}{8x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8x, the least common multiple of 8,8x.

$$\frac{7}{8}x\times 8x-3=y\times 8x$$

Multiply \frac{7}{8} and 8 to get 7.

$$7xx-3=y\times 8x$$

Multiply x and x to get x^{2}.

$$7x^{2}-3=y\times 8x$$

Swap sides so that all variable terms are on the left hand side.

$$y\times 8x=7x^{2}-3$$

The equation is in standard form.

$$8xy=7x^{2}-3$$

Divide both sides by 8x.

$$\frac{8xy}{8x}=\frac{7x^{2}-3}{8x}$$

Dividing by 8x undoes the multiplication by 8x.

$$y=\frac{7x^{2}-3}{8x}$$

Divide 7x^{2}-3 by 8x.

$$y=\frac{7x}{8}-\frac{3}{8x}$$

Solve for x

$$x=\frac{\sqrt{16y^{2}+21}+4y}{7}$$

$$x=\frac{-\sqrt{16y^{2}+21}+4y}{7}$$