Solve 7/8div(1/4+1/3)=

$$\frac { 7 } { 8 } \div ( \frac { 1 } { 4 } + \frac { 1 } { 3 } ) =$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Least common multiple of 4 and 3 is 12. Convert \frac{1}{4} and \frac{1}{3} to fractions with denominator 12.

$$\frac{\frac{7}{8}}{\frac{3}{12}+\frac{4}{12}}$$

Since \frac{3}{12} and \frac{4}{12} have the same denominator, add them by adding their numerators.

$$\frac{\frac{7}{8}}{\frac{3+4}{12}}$$

Add 3 and 4 to get 7.

$$\frac{\frac{7}{8}}{\frac{7}{12}}$$

Divide \frac{7}{8} by \frac{7}{12} by multiplying \frac{7}{8} by the reciprocal of \frac{7}{12}.

$$\frac{7}{8}\times \frac{12}{7}$$

Multiply \frac{7}{8} times \frac{12}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 12}{8\times 7}$$

Cancel out 7 in both numerator and denominator.

$$\frac{12}{8}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$