Solve 7/6-(1/4+1/3-1/2)=

$$\frac { 7 } { 6 } - ( \frac { 1 } { 4 } + \frac { 1 } { 3 } - \frac { 1 } { 2 } ) =$$

Evaluate

$$\frac{13}{12}\approx 1.083333333$$

Solution Steps

Least common multiple of 4 and 3 is 12. Convert \frac{1}{4} and \frac{1}{3} to fractions with denominator 12.

$$\frac{7}{6}-\left(\frac{3}{12}+\frac{4}{12}-\frac{1}{2}\right)$$

Since \frac{3}{12} and \frac{4}{12} have the same denominator, add them by adding their numerators.

$$\frac{7}{6}-\left(\frac{3+4}{12}-\frac{1}{2}\right)$$

Add 3 and 4 to get 7.

$$\frac{7}{6}-\left(\frac{7}{12}-\frac{1}{2}\right)$$

Least common multiple of 12 and 2 is 12. Convert \frac{7}{12} and \frac{1}{2} to fractions with denominator 12.

$$\frac{7}{6}-\left(\frac{7}{12}-\frac{6}{12}\right)$$

Since \frac{7}{12} and \frac{6}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{6}-\frac{7-6}{12}$$

Subtract 6 from 7 to get 1.

$$\frac{7}{6}-\frac{1}{12}$$

Least common multiple of 6 and 12 is 12. Convert \frac{7}{6} and \frac{1}{12} to fractions with denominator 12.

$$\frac{14}{12}-\frac{1}{12}$$

Since \frac{14}{12} and \frac{1}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-1}{12}$$

Subtract 1 from 14 to get 13.

$$\frac{13}{12}$$

Factor

$$\frac{13}{2 ^ {2} \cdot 3} = 1\frac{1}{12} = 1.0833333333333333$$