Solve 7/6+1/9*1/3-1/2

$$\frac { 7 } { 6 } + \frac { 1 } { 9 } \cdot \frac { 1 } { 3 } - \frac { 1 } { 2 }$$

Evaluate

$$\frac{19}{27}\approx 0.703703704$$

Solution Steps

Multiply \frac{1}{9} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{6}+\frac{1\times 1}{9\times 3}-\frac{1}{2}$$

Do the multiplications in the fraction \frac{1\times 1}{9\times 3}.

$$\frac{7}{6}+\frac{1}{27}-\frac{1}{2}$$

Least common multiple of 6 and 27 is 54. Convert \frac{7}{6} and \frac{1}{27} to fractions with denominator 54.

$$\frac{63}{54}+\frac{2}{54}-\frac{1}{2}$$

Since \frac{63}{54} and \frac{2}{54} have the same denominator, add them by adding their numerators.

$$\frac{63+2}{54}-\frac{1}{2}$$

Add 63 and 2 to get 65.

$$\frac{65}{54}-\frac{1}{2}$$

Least common multiple of 54 and 2 is 54. Convert \frac{65}{54} and \frac{1}{2} to fractions with denominator 54.

$$\frac{65}{54}-\frac{27}{54}$$

Since \frac{65}{54} and \frac{27}{54} have the same denominator, subtract them by subtracting their numerators.

$$\frac{65-27}{54}$$

Subtract 27 from 65 to get 38.

$$\frac{38}{54}$$

Reduce the fraction \frac{38}{54} to lowest terms by extracting and canceling out 2.

$$\frac{19}{27}$$

Factor

$$\frac{19}{3 ^ {3}} = 0.7037037037037037$$