Solve 7/5*(-3/8)+3/4*7/5

$$\frac { 7 } { 5 } \times ( \frac { - 3 } { 8 } ) + \frac { 3 } { 4 } \times \frac { 7 } { 5 }$$

Evaluate

$$\frac{21}{40}=0.525$$

Solution Steps

Fraction \frac{-3}{8} can be rewritten as -\frac{3}{8} by extracting the negative sign.

$$\frac{7}{5}\left(-\frac{3}{8}\right)+\frac{3}{4}\times \frac{7}{5}$$

Multiply \frac{7}{5} times -\frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-3\right)}{5\times 8}+\frac{3}{4}\times \frac{7}{5}$$

Do the multiplications in the fraction \frac{7\left(-3\right)}{5\times 8}.

$$\frac{-21}{40}+\frac{3}{4}\times \frac{7}{5}$$

Fraction \frac{-21}{40} can be rewritten as -\frac{21}{40} by extracting the negative sign.

$$-\frac{21}{40}+\frac{3}{4}\times \frac{7}{5}$$

Multiply \frac{3}{4} times \frac{7}{5} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{21}{40}+\frac{3\times 7}{4\times 5}$$

Do the multiplications in the fraction \frac{3\times 7}{4\times 5}.

$$-\frac{21}{40}+\frac{21}{20}$$

Least common multiple of 40 and 20 is 40. Convert -\frac{21}{40} and \frac{21}{20} to fractions with denominator 40.

$$-\frac{21}{40}+\frac{42}{40}$$

Since -\frac{21}{40} and \frac{42}{40} have the same denominator, add them by adding their numerators.

$$\frac{-21+42}{40}$$

Add -21 and 42 to get 21.

$$\frac{21}{40}$$

Factor

$$\frac{3 \cdot 7}{2 ^ {3} \cdot 5} = 0.525$$