Solve for t
t>0
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\frac{7}{4}t>-\frac{8}{3}t
Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.
\frac{7}{4}t+\frac{8}{3}t>0
Add \frac{8}{3}t to both sides.
\frac{53}{12}t>0
Combine \frac{7}{4}t and \frac{8}{3}t to get \frac{53}{12}t.
t>0
Product of two numbers is >0 if both are >0 or both are <0. Since \frac{53}{12}>0, t must be >0.
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