Solve 7/4-sqrt[3]{(3/2)^2+2^-1+1}=

$$\frac { 7 } { 4 } - \sqrt[ 3 ] { ( \frac { 3 } { 2 } ) ^ { 2 } + 2 ^ { - 1 } + 1 } =$$

Evaluate

$$-\frac{\sqrt[3]{30}}{2}+\frac{7}{4}\approx 0.196383747$$

Solution Steps

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$\frac{7}{4}-\sqrt[3]{\frac{9}{4}+2^{-1}+1}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$\frac{7}{4}-\sqrt[3]{\frac{9}{4}+\frac{1}{2}+1}$$

Add \frac{9}{4} and \frac{1}{2} to get \frac{11}{4}.

$$\frac{7}{4}-\sqrt[3]{\frac{11}{4}+1}$$

Add \frac{11}{4} and 1 to get \frac{15}{4}.

$$\frac{7}{4}-\sqrt[3]{\frac{15}{4}}$$

Factor

$$\frac{7 - 2 \sqrt[3]{30}}{4} = 0.1963837470230707$$