Solve 7/36*(-6/50)+20/36*(-6/50)

$$\frac { 7 } { 36 } \cdot ( - \frac { 6 } { 50 } ) + \frac { 20 } { 36 } \cdot ( - \frac { 6 } { 50 } )$$

Evaluate

$$-\frac{9}{100}=-0.09$$

Solution Steps

Reduce the fraction \frac{6}{50} to lowest terms by extracting and canceling out 2.

$$\frac{7}{36}\left(-\frac{3}{25}\right)+\frac{20}{36}\left(-\frac{6}{50}\right)$$

Multiply \frac{7}{36} times -\frac{3}{25} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-3\right)}{36\times 25}+\frac{20}{36}\left(-\frac{6}{50}\right)$$

Do the multiplications in the fraction \frac{7\left(-3\right)}{36\times 25}.

$$\frac{-21}{900}+\frac{20}{36}\left(-\frac{6}{50}\right)$$

Reduce the fraction \frac{-21}{900} to lowest terms by extracting and canceling out 3.

$$-\frac{7}{300}+\frac{20}{36}\left(-\frac{6}{50}\right)$$

Reduce the fraction \frac{20}{36} to lowest terms by extracting and canceling out 4.

$$-\frac{7}{300}+\frac{5}{9}\left(-\frac{6}{50}\right)$$

Reduce the fraction \frac{6}{50} to lowest terms by extracting and canceling out 2.

$$-\frac{7}{300}+\frac{5}{9}\left(-\frac{3}{25}\right)$$

Multiply \frac{5}{9} times -\frac{3}{25} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{7}{300}+\frac{5\left(-3\right)}{9\times 25}$$

Do the multiplications in the fraction \frac{5\left(-3\right)}{9\times 25}.

$$-\frac{7}{300}+\frac{-15}{225}$$

Reduce the fraction \frac{-15}{225} to lowest terms by extracting and canceling out 15.

$$-\frac{7}{300}-\frac{1}{15}$$

Least common multiple of 300 and 15 is 300. Convert -\frac{7}{300} and \frac{1}{15} to fractions with denominator 300.

$$-\frac{7}{300}-\frac{20}{300}$$

Since -\frac{7}{300} and \frac{20}{300} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-7-20}{300}$$

Subtract 20 from -7 to get -27.

$$\frac{-27}{300}$$

Reduce the fraction \frac{-27}{300} to lowest terms by extracting and canceling out 3.

$$-\frac{9}{100}$$

Factor

$$-\frac{9}{100} = -0.09$$