Solve 7/30+7/60+7/23

$$\frac { 7 } { 30 } + \frac { 7 } { 60 } + \frac { 7 } { 23 }$$

Evaluate

$$\frac{301}{460}\approx 0.654347826$$

Solution Steps

Least common multiple of 30 and 60 is 60. Convert \frac{7}{30} and \frac{7}{60} to fractions with denominator 60.

$$\frac{14}{60}+\frac{7}{60}+\frac{7}{23}$$

Since \frac{14}{60} and \frac{7}{60} have the same denominator, add them by adding their numerators.

$$\frac{14+7}{60}+\frac{7}{23}$$

Add 14 and 7 to get 21.

$$\frac{21}{60}+\frac{7}{23}$$

Reduce the fraction \frac{21}{60} to lowest terms by extracting and canceling out 3.

$$\frac{7}{20}+\frac{7}{23}$$

Least common multiple of 20 and 23 is 460. Convert \frac{7}{20} and \frac{7}{23} to fractions with denominator 460.

$$\frac{161}{460}+\frac{140}{460}$$

Since \frac{161}{460} and \frac{140}{460} have the same denominator, add them by adding their numerators.

$$\frac{161+140}{460}$$

Add 161 and 140 to get 301.

$$\frac{301}{460}$$

Factor

$$\frac{7 \cdot 43}{2 ^ {2} \cdot 5 \cdot 23} = 0.6543478260869565$$