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\frac{12}{3\left(x-1\right)}
Since \frac{7}{3\left(x-1\right)} and \frac{5}{3\left(x-1\right)} have the same denominator, add them by adding their numerators. Add 7 and 5 to get 12.
\frac{12}{3x-3}
Expand 3\left(x-1\right).
\frac{12}{3\left(x-1\right)}
Since \frac{7}{3\left(x-1\right)} and \frac{5}{3\left(x-1\right)} have the same denominator, add them by adding their numerators. Add 7 and 5 to get 12.
\frac{12}{3x-3}
Expand 3\left(x-1\right).