Solve 7/3x+1/3x=4x+55/3+7/3x

$$\frac { 7 } { 3 } x + \frac { 1 } { 3 } x = 4 x + \frac { 55 } { 3 } + \frac { 7 } { 3 } x$$

Solve for x

$$x=-5$$

Steps for Solving Linear Equation

Combine \frac{7}{3}x and \frac{1}{3}x to get \frac{8}{3}x.

$$\frac{8}{3}x=4x+\frac{55}{3}+\frac{7}{3}x$$

Combine 4x and \frac{7}{3}x to get \frac{19}{3}x.

$$\frac{8}{3}x=\frac{19}{3}x+\frac{55}{3}$$

Subtract \frac{19}{3}x from both sides.

$$\frac{8}{3}x-\frac{19}{3}x=\frac{55}{3}$$

Combine \frac{8}{3}x and -\frac{19}{3}x to get -\frac{11}{3}x.

$$-\frac{11}{3}x=\frac{55}{3}$$

Multiply both sides by -\frac{3}{11}, the reciprocal of -\frac{11}{3}.

$$x=\frac{55}{3}\left(-\frac{3}{11}\right)$$

Multiply \frac{55}{3} times -\frac{3}{11} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{55\left(-3\right)}{3\times 11}$$

Do the multiplications in the fraction \frac{55\left(-3\right)}{3\times 11}.

$$x=\frac{-165}{33}$$

Divide -165 by 33 to get -5.

$$x=-5$$