Solve 7/3(x+9/28)=20?

$$\frac { 7 } { 3 } ( x + \frac { 9 } { 28 } ) = 20 ?$$

Solve for x

$$x = \frac{33}{4} = 8\frac{1}{4} = 8.25$$

Steps for Solving Linear Equation

Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.

$$x+\frac{9}{28}=20\times \frac{3}{7}$$

Express 20\times \frac{3}{7} as a single fraction.

$$x+\frac{9}{28}=\frac{20\times 3}{7}$$

Multiply 20 and 3 to get 60.

$$x+\frac{9}{28}=\frac{60}{7}$$

Subtract \frac{9}{28} from both sides.

$$x=\frac{60}{7}-\frac{9}{28}$$

Least common multiple of 7 and 28 is 28. Convert \frac{60}{7} and \frac{9}{28} to fractions with denominator 28.

$$x=\frac{240}{28}-\frac{9}{28}$$

Since \frac{240}{28} and \frac{9}{28} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{240-9}{28}$$

Subtract 9 from 240 to get 231.

$$x=\frac{231}{28}$$

Reduce the fraction \frac{231}{28} to lowest terms by extracting and canceling out 7.

$$x=\frac{33}{4}$$