Solve 7/3+1/3y=-1

$$\frac { 7 } { 3 } + \frac { 1 } { 3 } y = - 1$$

Solve for y

$$y=-10$$

Steps for Solving Linear Equation

Subtract \frac{7}{3} from both sides.

$$\frac{1}{3}y=-1-\frac{7}{3}$$

Convert -1 to fraction -\frac{3}{3}.

$$\frac{1}{3}y=-\frac{3}{3}-\frac{7}{3}$$

Since -\frac{3}{3} and \frac{7}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}y=\frac{-3-7}{3}$$

Subtract 7 from -3 to get -10.

$$\frac{1}{3}y=-\frac{10}{3}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$y=-\frac{10}{3}\times 3$$

Cancel out 3 and 3.

$$y=-10$$