Solve 7/2-2/3*(3/2+1)=

$$\frac { 7 } { 2 } - \frac { 2 } { 3 } \cdot ( \frac { 3 } { 2 } + 1 ) =$$

Evaluate

$$\frac{11}{6}\approx 1.833333333$$

Solution Steps

Convert 1 to fraction \frac{2}{2}.

$$\frac{7}{2}-\frac{2}{3}\left(\frac{3}{2}+\frac{2}{2}\right)$$

Since \frac{3}{2} and \frac{2}{2} have the same denominator, add them by adding their numerators.

$$\frac{7}{2}-\frac{2}{3}\times \frac{3+2}{2}$$

Add 3 and 2 to get 5.

$$\frac{7}{2}-\frac{2}{3}\times \frac{5}{2}$$

Multiply \frac{2}{3} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{2}-\frac{2\times 5}{3\times 2}$$

Cancel out 2 in both numerator and denominator.

$$\frac{7}{2}-\frac{5}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{7}{2} and \frac{5}{3} to fractions with denominator 6.

$$\frac{21}{6}-\frac{10}{6}$$

Since \frac{21}{6} and \frac{10}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-10}{6}$$

Subtract 10 from 21 to get 11.

$$\frac{11}{6}$$

Factor

$$\frac{11}{2 \cdot 3} = 1\frac{5}{6} = 1.8333333333333333$$