Solve 7/2*(13/6+9/9)=

$$\frac { 7 } { 2 } \cdot ( \frac { 13 } { 6 } + \frac { 9 } { 9 } ) =$$

Evaluate

$$\frac{133}{12}\approx 11.083333333$$

Solution Steps

Divide 9 by 9 to get 1.

$$\frac{7}{2}\left(\frac{13}{6}+1\right)$$

Convert 1 to fraction \frac{6}{6}.

$$\frac{7}{2}\left(\frac{13}{6}+\frac{6}{6}\right)$$

Since \frac{13}{6} and \frac{6}{6} have the same denominator, add them by adding their numerators.

$$\frac{7}{2}\times \frac{13+6}{6}$$

Add 13 and 6 to get 19.

$$\frac{7}{2}\times \frac{19}{6}$$

Multiply \frac{7}{2} times \frac{19}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 19}{2\times 6}$$

Do the multiplications in the fraction \frac{7\times 19}{2\times 6}.

$$\frac{133}{12}$$

Factor

$$\frac{7 \cdot 19}{2 ^ {2} \cdot 3} = 11\frac{1}{12} = 11.083333333333334$$