Solve 7/2*(13/6+9/1)

$$\frac { 7 } { 2 } \cdot ( \frac { 13 } { 6 } + \frac { 9 } { 1 } )$$

Evaluate

$$\frac{469}{12}\approx 39.083333333$$

Solution Steps

Anything divided by one gives itself.

$$\frac{7}{2}\left(\frac{13}{6}+9\right)$$

Convert 9 to fraction \frac{54}{6}.

$$\frac{7}{2}\left(\frac{13}{6}+\frac{54}{6}\right)$$

Since \frac{13}{6} and \frac{54}{6} have the same denominator, add them by adding their numerators.

$$\frac{7}{2}\times \frac{13+54}{6}$$

Add 13 and 54 to get 67.

$$\frac{7}{2}\times \frac{67}{6}$$

Multiply \frac{7}{2} times \frac{67}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 67}{2\times 6}$$

Do the multiplications in the fraction \frac{7\times 67}{2\times 6}.

$$\frac{469}{12}$$

Factor

$$\frac{7 \cdot 67}{2 ^ {2} \cdot 3} = 39\frac{1}{12} = 39.083333333333336$$