Solve 7/17+1/4+3/8?

$$\frac { 7 } { 17 } + \frac { 1 } { 4 } + \frac { 3 } { 8 } ?$$

Evaluate

$$\frac{141}{136}\approx 1.036764706$$

Solution Steps

Least common multiple of 17 and 4 is 68. Convert \frac{7}{17} and \frac{1}{4} to fractions with denominator 68.

$$\frac{28}{68}+\frac{17}{68}+\frac{3}{8}$$

Since \frac{28}{68} and \frac{17}{68} have the same denominator, add them by adding their numerators.

$$\frac{28+17}{68}+\frac{3}{8}$$

Add 28 and 17 to get 45.

$$\frac{45}{68}+\frac{3}{8}$$

Least common multiple of 68 and 8 is 136. Convert \frac{45}{68} and \frac{3}{8} to fractions with denominator 136.

$$\frac{90}{136}+\frac{51}{136}$$

Since \frac{90}{136} and \frac{51}{136} have the same denominator, add them by adding their numerators.

$$\frac{90+51}{136}$$

Add 90 and 51 to get 141.

$$\frac{141}{136}$$

Factor

$$\frac{3 \cdot 47}{2 ^ {3} \cdot 17} = 1\frac{5}{136} = 1.036764705882353$$