Solve 7/16-15/8+1/3=

$$\frac { 7 } { 16 } - \frac { 15 } { 8 } + \frac { 1 } { 3 } =$$

Evaluate

$$-\frac{53}{48}\approx -1.104166667$$

Solution Steps

Least common multiple of 16 and 8 is 16. Convert \frac{7}{16} and \frac{15}{8} to fractions with denominator 16.

$$\frac{7}{16}-\frac{30}{16}+\frac{1}{3}$$

Since \frac{7}{16} and \frac{30}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-30}{16}+\frac{1}{3}$$

Subtract 30 from 7 to get -23.

$$-\frac{23}{16}+\frac{1}{3}$$

Least common multiple of 16 and 3 is 48. Convert -\frac{23}{16} and \frac{1}{3} to fractions with denominator 48.

$$-\frac{69}{48}+\frac{16}{48}$$

Since -\frac{69}{48} and \frac{16}{48} have the same denominator, add them by adding their numerators.

$$\frac{-69+16}{48}$$

Add -69 and 16 to get -53.

$$-\frac{53}{48}$$

Factor

$$-\frac{53}{48} = -1\frac{5}{48} = -1.1041666666666667$$