Solve 7/12+3/6+1/2=

$$\frac { 7 } { 12 } + \frac { 3 } { 6 } + \frac { 1 } { 2 } =$$

Evaluate

$$\frac{19}{12}\approx 1.583333333$$

Solution Steps

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{7}{12}+\frac{1}{2}+\frac{1}{2}$$

Least common multiple of 12 and 2 is 12. Convert \frac{7}{12} and \frac{1}{2} to fractions with denominator 12.

$$\frac{7}{12}+\frac{6}{12}+\frac{1}{2}$$

Since \frac{7}{12} and \frac{6}{12} have the same denominator, add them by adding their numerators.

$$\frac{7+6}{12}+\frac{1}{2}$$

Add 7 and 6 to get 13.

$$\frac{13}{12}+\frac{1}{2}$$

Least common multiple of 12 and 2 is 12. Convert \frac{13}{12} and \frac{1}{2} to fractions with denominator 12.

$$\frac{13}{12}+\frac{6}{12}$$

Since \frac{13}{12} and \frac{6}{12} have the same denominator, add them by adding their numerators.

$$\frac{13+6}{12}$$

Add 13 and 6 to get 19.

$$\frac{19}{12}$$

Factor

$$\frac{19}{2 ^ {2} \cdot 3} = 1\frac{7}{12} = 1.5833333333333333$$