Solve 7/10+3/8-1/6

$$\frac { 7 } { 10 } + \frac { 3 } { 8 } - \frac { 1 } { 6 }$$

Evaluate

$$\frac{109}{120}\approx 0.908333333$$

Solution Steps

Least common multiple of 10 and 8 is 40. Convert \frac{7}{10} and \frac{3}{8} to fractions with denominator 40.

$$\frac{28}{40}+\frac{15}{40}-\frac{1}{6}$$

Since \frac{28}{40} and \frac{15}{40} have the same denominator, add them by adding their numerators.

$$\frac{28+15}{40}-\frac{1}{6}$$

Add 28 and 15 to get 43.

$$\frac{43}{40}-\frac{1}{6}$$

Least common multiple of 40 and 6 is 120. Convert \frac{43}{40} and \frac{1}{6} to fractions with denominator 120.

$$\frac{129}{120}-\frac{20}{120}$$

Since \frac{129}{120} and \frac{20}{120} have the same denominator, subtract them by subtracting their numerators.

$$\frac{129-20}{120}$$

Subtract 20 from 129 to get 109.

$$\frac{109}{120}$$

Factor

$$\frac{109}{2 ^ {3} \cdot 3 \cdot 5} = 0.9083333333333333$$