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\frac{\frac{42+5}{6}-\frac{1}{4}\times \frac{9}{3}}{\frac{3}{5}\times \frac{7}{4}+\frac{3}{7}}
Multiply 7 and 6 to get 42.
\frac{\frac{47}{6}-\frac{1}{4}\times \frac{9}{3}}{\frac{3}{5}\times \frac{7}{4}+\frac{3}{7}}
Add 42 and 5 to get 47.
\frac{\frac{47}{6}-\frac{1}{4}\times 3}{\frac{3}{5}\times \frac{7}{4}+\frac{3}{7}}
Divide 9 by 3 to get 3.
\frac{\frac{47}{6}-\frac{3}{4}}{\frac{3}{5}\times \frac{7}{4}+\frac{3}{7}}
Multiply \frac{1}{4} and 3 to get \frac{3}{4}.
\frac{\frac{94}{12}-\frac{9}{12}}{\frac{3}{5}\times \frac{7}{4}+\frac{3}{7}}
Least common multiple of 6 and 4 is 12. Convert \frac{47}{6} and \frac{3}{4} to fractions with denominator 12.
\frac{\frac{94-9}{12}}{\frac{3}{5}\times \frac{7}{4}+\frac{3}{7}}
Since \frac{94}{12} and \frac{9}{12} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{85}{12}}{\frac{3}{5}\times \frac{7}{4}+\frac{3}{7}}
Subtract 9 from 94 to get 85.
\frac{\frac{85}{12}}{\frac{3\times 7}{5\times 4}+\frac{3}{7}}
Multiply \frac{3}{5} times \frac{7}{4} by multiplying numerator times numerator and denominator times denominator.
\frac{\frac{85}{12}}{\frac{21}{20}+\frac{3}{7}}
Do the multiplications in the fraction \frac{3\times 7}{5\times 4}.
\frac{\frac{85}{12}}{\frac{147}{140}+\frac{60}{140}}
Least common multiple of 20 and 7 is 140. Convert \frac{21}{20} and \frac{3}{7} to fractions with denominator 140.
\frac{\frac{85}{12}}{\frac{147+60}{140}}
Since \frac{147}{140} and \frac{60}{140} have the same denominator, add them by adding their numerators.
\frac{\frac{85}{12}}{\frac{207}{140}}
Add 147 and 60 to get 207.
\frac{85}{12}\times \frac{140}{207}
Divide \frac{85}{12} by \frac{207}{140} by multiplying \frac{85}{12} by the reciprocal of \frac{207}{140}.
\frac{85\times 140}{12\times 207}
Multiply \frac{85}{12} times \frac{140}{207} by multiplying numerator times numerator and denominator times denominator.
\frac{11900}{2484}
Do the multiplications in the fraction \frac{85\times 140}{12\times 207}.
\frac{2975}{621}
Reduce the fraction \frac{11900}{2484} to lowest terms by extracting and canceling out 4.