Solve 7*(-7)^3*(-3)^2*1/2/6

$$\frac { 7 \cdot ( - 7 ) ^ { 3 } \cdot ( - 3 ) ^ { 2 } \cdot \frac { 1 } { 2 } } { 6 }$$

Evaluate

$$-\frac{7203}{4}=-1800.75$$

Solution Steps

Calculate -7 to the power of 3 and get -343.

$$\frac{7\left(-343\right)\left(-3\right)^{2}\times \frac{1}{2}}{6}$$

Multiply 7 and -343 to get -2401.

$$\frac{-2401\left(-3\right)^{2}\times \frac{1}{2}}{6}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{-2401\times 9\times \frac{1}{2}}{6}$$

Multiply -2401 and 9 to get -21609.

$$\frac{-21609\times \frac{1}{2}}{6}$$

Multiply -21609 and \frac{1}{2} to get \frac{-21609}{2}.

$$\frac{\frac{-21609}{2}}{6}$$

Fraction \frac{-21609}{2} can be rewritten as -\frac{21609}{2} by extracting the negative sign.

$$\frac{-\frac{21609}{2}}{6}$$

Express \frac{-\frac{21609}{2}}{6} as a single fraction.

$$\frac{-21609}{2\times 6}$$

Multiply 2 and 6 to get 12.

$$\frac{-21609}{12}$$

Reduce the fraction \frac{-21609}{12} to lowest terms by extracting and canceling out 3.

$$-\frac{7203}{4}$$

Factor

$$-\frac{7203}{4} = -1800\frac{3}{4} = -1800.75$$