Solve 7^6*(7^-2)^4/7^-3

$$\frac { 7 ^ { 6 } \times ( 7 ^ { - 2 } ) ^ { 4 } } { 7 ^ { - 3 } }$$

Evaluate

$$7$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply -2 and 4 to get -8.

$$\frac{7^{6}\times 7^{-8}}{7^{-3}}$$

To multiply powers of the same base, add their exponents. Add 6 and -8 to get -2.

$$\frac{7^{-2}}{7^{-3}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract -3 from -2 to get 1.

$$7^{1}$$

Calculate 7 to the power of 1 and get 7.

$$7$$

Factor

$$7$$