Solve 7^2/3-1/3-3+3^3

$$\frac { 7 ^ { 2 } } { 3 } - \frac { 1 } { 3 } - 3 + 3 ^ { 3 }$$

Evaluate

$$40$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$\frac{49}{3}-\frac{1}{3}-3+3^{3}$$

Since \frac{49}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-1}{3}-3+3^{3}$$

Subtract 1 from 49 to get 48.

$$\frac{48}{3}-3+3^{3}$$

Divide 48 by 3 to get 16.

$$16-3+3^{3}$$

Subtract 3 from 16 to get 13.

$$13+3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$13+27$$

Add 13 and 27 to get 40.

$$40$$

Factor

$$2^{3}\times 5$$