Evaluate
\frac{8\sqrt{3}}{3x}
Differentiate w.r.t. x
-\frac{8\sqrt{3}}{3x^{2}}
Graph
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\frac{16}{2\sqrt{3}x}
Add 7 and 9 to get 16.
\frac{16\sqrt{3}}{2\left(\sqrt{3}\right)^{2}x}
Rationalize the denominator of \frac{16}{2\sqrt{3}x} by multiplying numerator and denominator by \sqrt{3}.
\frac{16\sqrt{3}}{2\times 3x}
The square of \sqrt{3} is 3.
\frac{8\sqrt{3}}{3x}
Cancel out 2 in both numerator and denominator.
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