Solve 7+|5-3|+3^2/6-2

$$\frac { 7 + | 5 - 3 | + 3 ^ { 2 } } { 6 - 2 }$$

Evaluate

$$\frac{9}{2}=4.5$$

Solution Steps

Subtract 3 from 5 to get 2.

$$\frac{7+|2|+3^{2}}{6-2}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 2 is 2.

$$\frac{7+2+3^{2}}{6-2}$$

Add 7 and 2 to get 9.

$$\frac{9+3^{2}}{6-2}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{9+9}{6-2}$$

Add 9 and 9 to get 18.

$$\frac{18}{6-2}$$

Subtract 2 from 6 to get 4.

$$\frac{18}{4}$$

Reduce the fraction \frac{18}{4} to lowest terms by extracting and canceling out 2.

$$\frac{9}{2}$$

Factor

$$\frac{3 ^ {2}}{2} = 4\frac{1}{2} = 4.5$$