Solve 64/3-8+8-(6/3-2+4)

$$\frac { 64 } { 3 } - 8 + 8 - ( \frac { 6 } { 3 } - 2 + 4 )$$

Evaluate

$$\frac{52}{3}\approx 17.333333333$$

Solution Steps

Convert 8 to fraction \frac{24}{3}.

$$\frac{64}{3}-\frac{24}{3}+8-\left(\frac{6}{3}-2+4\right)$$

Since \frac{64}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{64-24}{3}+8-\left(\frac{6}{3}-2+4\right)$$

Subtract 24 from 64 to get 40.

$$\frac{40}{3}+8-\left(\frac{6}{3}-2+4\right)$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{40}{3}+\frac{24}{3}-\left(\frac{6}{3}-2+4\right)$$

Since \frac{40}{3} and \frac{24}{3} have the same denominator, add them by adding their numerators.

$$\frac{40+24}{3}-\left(\frac{6}{3}-2+4\right)$$

Add 40 and 24 to get 64.

$$\frac{64}{3}-\left(\frac{6}{3}-2+4\right)$$

Divide 6 by 3 to get 2.

$$\frac{64}{3}-\left(2-2+4\right)$$

Subtract 2 from 2 to get 0.

$$\frac{64}{3}-4$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{64}{3}-\frac{12}{3}$$

Since \frac{64}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{64-12}{3}$$

Subtract 12 from 64 to get 52.

$$\frac{52}{3}$$

Factor

$$\frac{2 ^ {2} \cdot 13}{3} = 17\frac{1}{3} = 17.333333333333332$$